Step 1:
First, we can use the property of summation to break the sum into three separate sums and pull out the constants:
$$\sum_{k=1}^{20} 100\left(k^{2}-5 k+1\right) = 100\left(\sum_{k=1}^{20} k^{2} - 5\sum_{k=1}^{20} k + \sum_{k=1}^{20} 1\right)$$
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