Question
In the following exercises, use the substitution $(b+x)^{r} (b+a)^{r}\left(1+\frac{x-a}{b+a}\right)^{r}$ in the binomial expansion to find the Taylor series of each function with the given center. $$\sqrt{x^{2}+2} \text { at } a=0$$
Step 1
Step 1: First, we rewrite the function $\sqrt{x^{2}+2}$ as $\sqrt{2(1+\frac{x^{2}}{2})}$, which can be further simplified to $\sqrt{2}\sqrt{1+\frac{x^{2}}{2}}$. Show more…
Show all steps
Your feedback will help us improve your experience
Thane Stiles and 87 other Calculus 2 / BC educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
In the following exercises, use the substitution $(b+x)^{r} (b+a)^{r}\left(1+\frac{x-a}{b+a}\right)^{r}$ in the binomial expansion to find the Taylor series of each function with the given center. $$ \sqrt{x+2} \text { at } a=0 $$
Power Series
Working with Taylor Series
In the following exercises, use the substitution $(b+x)^{r} (b+a)^{r}\left(1+\frac{x-a}{b+a}\right)^{r}$ in the binomial expansion to find the Taylor series of each function with the given center. $$ \sqrt{x+2} \text { at } a=1 $$
In the following exercises, use the substitution $(b+x)^{r} (b+a)^{r}\left(1+\frac{x-a}{b+a}\right)^{r}$ in the binomial expansion to find the Taylor series of each function with the given center. $$ \sqrt{2 x-x^{2}} \text { at } a=1 \text { (Hint: } 2 x-x^{2}=1-(x-1)^{2} ) $$
Transcript
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD