00:01
So for this problem, you want to find the atomic mass of oxygen, if we know some information about the formation of carbon monoxide, specifically that we have 2 .445 grams of carbon, which combines with 3 .257 grams of oxygen.
00:21
So the important thing here is that the atomic mass is going to be the exact same number as the molar mass, even though the units are going to be a bit different.
00:32
And because we know that our compound is carbon monoxide, we know the multiple ratio.
00:39
So, because we know the multiple ratio, we know that for every carbon atom, there must be one oxygen atom because there's only one of each in this compound.
00:47
So the multiple ratio is one to one.
00:55
So in other words, every oxygen atom must correspond with every carbon atom.
00:59
And from here, we can set up an easy proportion because we know that we can find the expression for the number of.....