00:01
Our question is, in the given network of capacitors, shown the result, given that c1, c2, c3 is 400 pfrared, and c4, c5, c6 is 200 pfarrad, the effective capacitance of the circle between x and y, we have to calculate.
00:13
First, we will assume that c1 is equal to c2 is equal to c3 is equal to c3, that is 400 peak of it.
00:24
And c4 is equal to c5 equals to c6 that is equals to c -6, that is equal to c -tash.
00:33
That is 200 be propelled.
00:40
This means that c -is equals to 2c -dash.
00:49
As these two capacitors, c -3 and c -4, are in parallel, so we will just add this, that is c -3 plus c -4.
01:06
And this parallel combination is in series with this c2...