In the hydrolysis of ATP to ADP and $P_{i}$, the equilibrium concentration of ATP is too small to be measured accurately. A better way of determining $K_{\mathrm{eq}^{\prime}}^{\prime},$ and hence $\Delta G^{\circ \prime}$ of this reaction, is to break it up into two steps whose values of $\Delta G^{\circ \prime}$ can be accurately determined. This has been done using the following pair of reactions (the first being catalyzed by glutamine synthetase):
(1) $\mathrm{ATP}+$ glutamate $+\mathrm{NH}_{4}^{+} \rightleftharpoons \mathrm{ADP}+\mathrm{P}_{i}+$ glutamine $+\mathrm{H}^{+}$
\[\Delta G_{1}^{\circ \prime}=-16.3 \mathrm{kJ} \cdot \mathrm{mol}^{-1}\]
(2) Glutamate $+\mathrm{NH}_{4}^{+} \rightleftharpoons$ glutamine $+\mathrm{H}_{2} \mathrm{O}+\mathrm{H}^{+}$
\[\Delta G_{2}^{\circ \prime}=-14.2 \mathrm{kJ} \cdot \mathrm{mol}^{-1}\]
What is the $\Delta G^{\circ \prime}$ of ATP hydrolysis according to these data?