Question

In the multiplicative group $F^{\times}$of a field $F$ of order 43, let $\alpha$ have order 7 and let $\epsilon$ have order 3 . Working in the group $G L(3,43)$, let $$ a=\left[\begin{array}{ccc} \alpha & 0 & 0 \\ 0 & \alpha^4 & 0 \\ 0 & 0 & \alpha^2 \end{array}\right] \quad \text { and } \quad b=\left[\begin{array}{ccc} 0 & 1 & 0 \\ 0 & 0 & 1 \\ e & 0 & 0 \end{array}\right] \text {. } $$ Show that $A=\langle a, b\rangle$ is noncyclic of order 63 , and that its natural action on the vector space $V$ of order $43^3$ is Frobenius.

   In the multiplicative group $F^{\times}$of a field $F$ of order 43, let $\alpha$ have order 7 and let $\epsilon$ have order 3 . Working in the group $G L(3,43)$, let
$$
a=\left[\begin{array}{ccc}
\alpha & 0 & 0 \\
0 & \alpha^4 & 0 \\
0 & 0 & \alpha^2
\end{array}\right] \quad \text { and } \quad b=\left[\begin{array}{ccc}
0 & 1 & 0 \\
0 & 0 & 1 \\
e & 0 & 0
\end{array}\right] \text {. }
$$

Show that $A=\langle a, b\rangle$ is noncyclic of order 63 , and that its natural action on the vector space $V$ of order $43^3$ is Frobenius.
Show more…
Finite Group Theory (GSM92)
Finite Group Theory (GSM92)
I. Martin Isaacs 1st Edition
Chapter 6, Problem 2 ↓

Instant Answer

verified

Step 1

The matrix \( a \) is a diagonal matrix with entries \( \alpha, \alpha^4, \alpha^2 \). Since \( \alpha \) has order 7, we can find the orders of each diagonal entry: - The order of \( \alpha \) is 7. - The order of \( \alpha^4 \) is \( \frac{7}{\gcd(4, 7)} = 7  Show more…

Show all steps

lock
AceChat toggle button
Close icon
Ace pointing down

Please give Ace some feedback

Your feedback will help us improve your experience

Thumb up icon Thumb down icon
Thanks for your feedback!
Profile picture
In the multiplicative group $F^{\times}$of a field $F$ of order 43, let $\alpha$ have order 7 and let $\epsilon$ have order 3 . Working in the group $G L(3,43)$, let $$ a=\left[\begin{array}{ccc} \alpha & 0 & 0 \\ 0 & \alpha^4 & 0 \\ 0 & 0 & \alpha^2 \end{array}\right] \quad \text { and } \quad b=\left[\begin{array}{ccc} 0 & 1 & 0 \\ 0 & 0 & 1 \\ e & 0 & 0 \end{array}\right] \text {. } $$ Show that $A=\langle a, b\rangle$ is noncyclic of order 63 , and that its natural action on the vector space $V$ of order $43^3$ is Frobenius.
Close icon
Play audio
Feedback
Powered by NumerAI
*

Labs

-

Want to see this concept in action?

NEW

Explore this concept interactively to see how it behaves as you change inputs.

View Labs

*

Key Concepts

-
Finite Fields and Their Multiplicative Groups
A finite field is a field with a finite number of elements, and one of its main features is that its multiplicative group (the set of nonzero elements under multiplication) is cyclic. This means that there exists an element, called a generator, such that every nonzero element of the field can be written as some power of this generator. Understanding this concept is key when selecting elements of specific orders from the field.
Order of an Element
In group theory, the order of an element is defined as the smallest positive integer for which raising the element to that power yields the identity element. This concept is central to the problem since specific elements are chosen to have predetermined orders, and these orders are used to construct a group with overall order 63.
Cyclic and Noncyclic Groups
A cyclic group is one that can be generated by a single element, whereas a noncyclic group cannot be reduced to the powers of a single element. The problem involves showing that the group generated by the given matrices is noncyclic, highlighting the importance of understanding how group structure and the orders of elements interact to produce groups with more complex compositions.
General Linear Groups
The general linear group, denoted GL(n, q), is the group of all invertible n×n matrices over a finite field with q elements. These groups form key examples in linear algebra and representation theory, and studying their subgroups—such as the one given in the problem—illustrates how matrix groups can exhibit rich finite group structures.
Frobenius Group Action
A Frobenius action refers to a group action in which every nonidentity element fixes at most one element of the set on which the group acts. This concept is particularly important in characterizing group actions with a strong form of regularity and asymmetry. In the context of the problem, showing that the natural action on the vector space is Frobenius involves verifying that the fixed-point structure conforms to the Frobenius condition.
Semidirect Products
A semidirect product is a way of constructing a new group from two subgroups, one of which is normal. It generalizes the concept of a direct product by allowing a nontrivial interaction between the subgroups. In situations like the given problem, groups of composite order (such as 63) are often understood as semidirect products, which explains their noncyclic nature and the specific way in which different cyclic subgroups combine.

*

Recommended Videos

-
lets-denote-the-six-elements-of-gl2z2-by-0-a-8-hj-s-c-p-e-4j-a-what-is-the-order-of-each-element-b-how-many-subgroups-of-order-2-does-this-group-have-please-list-them-c-how-many-subgroups-of-76803

Let's denote the six elements of GL(2,Z2) by A = [0 1] [1 0] B = [1 0] [0 1] C = [1 1] [0 1] D = [0 1] [1 1] E = [1 1] [1 0] F = [0 1] [0 1] (a) What is the order of each element? (b) How many subgroups of order 2 does this group have? Please list them. (c) How many subgroups of order 3 does this group have? Please list them.

let-p-be-prime-and-let-gl2fp-be-the-group-of-2-x-2-invertible-matrices-over-fp-let-g-glz-fp-be-the-subgroup-of-upper-triangular-matrices-g-bc-fp-det-you-may-use-without-proof-the-fact-that-g-37588

Let p be a prime and let GL2(Fp) be the group of 2 x 2 invertible matrices over Fp. Let G ⊂ GL2(Fp) be the subgroup of upper-triangular matrices: G = { [a, b; 0, c] : a, b, c ∈ Fp, det = ac ≠ 0 } You may use without proof the fact that G is a subgroup. (a) Show that the function ϕ: G → (Z/pZ)* x (Z/pZ)* defined by ϕ([a, b; 0, c]) = (a, c) is a surjective group homomorphism. (b) Show that G is a solvable group. (It will help to examine ker ϕ.)

Need help? Use Ace
Ace is your personal tutor. It breaks down any question with clear steps so you can learn.
Start Using Ace
Ace is your personal tutor for learning
Step-by-step explanations
Instant summaries
Summarize YouTube videos
Understand textbook images or PDFs
Study tools like quizzes and flashcards
Listen to your notes as a podcast
Continue solving this problem
Create a free account to:
  • View full step-by-step solution
  • Ask follow-up questions with Ace AI
  • Save progress and study later
Continue Free
Join the community

18,000,000+

Students on Numerade


Trusted by students at 8,000+ universities

Numerade

Get step-by-step video solution
from top educators

Continue with Clever
or



By creating an account, you agree to the Terms of Service and Privacy Policy
Already have an account? Log In

A free answer
just for you

Watch the video solution with this free unlock.

Numerade

Log in to watch this video
...and 100,000,000 more!


EMAIL

PASSWORD

OR
Continue with Clever