00:01
Hello friends in the figure if you see there is a planetary gear system so the radius of gears a b c d radius of the gear a v c and d each of 3 inch i couldn't draw the diagram here it is very difficult to draw radius of outer gear e is given 9 inch it is known that gair a has constant and angular velocity 150 rpm in clockwise direction and outer gear e is stationary so omega e is given zero we have to calculate acceleration of the tooth of gear d with gear a and gear b so we have to find the acceleration of of the gear d that is in contact with a and e.
02:16
Let us start solving it.
02:24
First we will do the velocity analysis.
02:40
T is twith of gair d in contact with a.
02:46
T we are assuming of gerd in contact to ger d and its tangential velocity is r into omega a.
03:21
R is given inch, so 3 into omega a inch per second.
03:34
Since velocity of e gap is given 0, so e is instantaneous center of gear d.
04:07
So velocity of the gear you can write 2r equating both you will get just a moment equating both 3 omega a is called to 2, 3 inch, omega into d.
04:43
So angular velocity of gear d will be half of angular velocity of gear a.
05:05
Now velocity of d will be r into omega d.
05:17
R is 3 inch.
05:20
Omega is omega a by 2.
05:25
So you will get 1 .5 omega a inch per second for spider...