Question
In the question number the rope is(b) $10 \mathrm{~ms}^{-2}$(a) $5 \mathrm{~m} 5^{-2}$(d) $20 \mathrm{~ms}^{-2}$(c) $15 \mathrm{~m} \mathrm{~s}^{-2}$. $\mathrm{H}$ and radius $R$ is rotating
Step 1
4 \, \text{m}$. Show more…
Show all steps
Your feedback will help us improve your experience
Dheeraj Sharma and 81 other Physics 101 Mechanics educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
For a particle rotating in a vertical circle with uniform speed, the maximum and minimum tension in the string are in the ratio $5: 3$. If the radius of vertical circle is $2 \mathrm{~m}$, the speed of revolving body is $\left(g=10 \mathrm{~m} / \mathrm{s}^{2}\right)$ (A) $\sqrt{5} \mathrm{~m} / \mathrm{s}$ (B) $4 \sqrt{5} \mathrm{~m} / \mathrm{s}$ (C) $5 \mathrm{~m} / \mathrm{s}$ (D) $10 \mathrm{~m} / \mathrm{s}$
A rope can withstand a maximum tension of pi^2 kg wt . A body of mass 2 kg is tied to this rope and revolved in a horizontal circle of radius 5 m . The maximum frequency of revolution possible is [g = 10 m/s^2] A. 0.2 rev/s B. 0.5 rev/s C. 1 rev/s D. 2 rev/s
A centripetal acceleration of 2.5 ms ^ - 2 acts on a mass of 10 kg which forces the mass to execute uniform circular motion. The radius of the circle is 10 m , then with which the mass travels is [ ] A. 5 m s ^ - 1 B. 6 ms ^ - 1 C. 7 m s ^ - 1 D. 8 m s ^ - 1
Transcript
Watch the video solution with this free unlock.
EMAIL
PASSWORD