In the reaction $\mathrm{BaO}_2(\mathrm{~s}) \Longleftrightarrow \mathrm{BaO}(\mathrm{s})+\mathrm{O}_2(\mathrm{~g})$; $\Delta \mathrm{H}=+$ ve. In equilibrium condition, pressure of $\mathrm{O}_2$ depends on
(a) increase mass of $\mathrm{BaO}_2$
(b) increase mass of BaO
(c) temperature of equilibrium
(d) mass of $\mathrm{BaO}_2$ and BaO both