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All right, guys, we're doing problem 126 in chapter 7.
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So in the second row of the prr table, borrelium, nitrogen, neon, all have endothermic or unfavorable electron infinities.
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Whereas the second row, other second row elements have exothermic or favorable electron phase.
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We rationalize why berylion, nitrogen, neon, have unfavorable electron infinities.
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So let's get an energy level diagram.
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So these are all in n equals two, so we're going to have two s electrons and also two p electrons.
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So with beryllium, we only have electrons in the 2s orbital.
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So now, if we want to put another electron to beryllium, we have to access our 2p orbital, which is higher in energy.
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So if we were to do that, it would just not be a favorable reaction because we are moving from a lower energy level to a higher energy level for nitrogen.
00:53
We have, as nitrogen has 2s electrons and 3, 2p electrons.
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So now, what happens if you were to add another electron to nitrogen? you would be pairing up these electrons.
01:08
You'd be putting us, each orbital has one electron, so you'd have, if you add another one, you have to pair it up...