In the set up shown, the floor is smooth, $m_{1}=1 \mathrm{~kg}, \mathrm{~m}_{2}=10 \mathrm{~kg}$ and the coefficient of friction between their surfaces is $\mu=0.6$. Assume the surface of $\mathrm{m}$, is large enough so that when $\mathrm{m}_{2}$ is given a velocity $\mathrm{v}$ as shown, it slips on $\mathrm{m}_{1}$ till
the spring is compressed to maximum i.e., till $m_{1}$ stops. The spring constant $\mathrm{k}=200 \mathrm{~N} \mathrm{~m}^{-1}$. The maximum velocity achieved by $\mathrm{m}_{1}$ is
(a) $3 \sqrt{2} \mathrm{~m} \mathrm{~s}^{-1}$
(b) $5 \sqrt{2} \mathrm{~m} \mathrm{~s}^{-1}$
(c) $3 \sqrt{3} \mathrm{~m} \mathrm{~s}^{-1}$
(d) $\sqrt{7} \mathrm{~m} \mathrm{~s}^{-1}$