00:01
You have an object that's going to roll down an incline that's 13 degrees below the horizontal.
00:06
You're told the length of the run is 55 feet.
00:10
Based on the geometry of the problem, you can see that the incline of that is also 13 degrees.
00:17
Alternate interior angles are equal.
00:19
And you're asked to find the maximum possible acceleration of that object down the incline.
00:25
So the part of the acceleration that's parallel to the incline is equal to g -sign theta according to the text.
00:35
And so you get 9 .8 sign of 13 degrees.
00:40
Oops.
00:46
You solve that and you get an answer of 2 .2 meters per second squared.
00:56
So that's the answer for part a.
01:00
For part b, you have to find if the car or the object, starts from rest, so vi is equal to zero.
01:12
And it accelerates with that acceleration for the full 55 feet, find the final velocity vf.
01:19
So we know a from the previous problem, we know vi, the problem is that the displacement is 55 feet.
01:27
We need to convert that to meters.
01:29
If you look up the relationship between feet and meters, you'll find that there is 0 .30, 0 .38 meters and every one foot...