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In $\triangle A B C, A B=\sqrt{7 x+5, B C}=\sqrt{5 x+15},$ and $A C=\sqrt{2 x}$a. If $A B=B C,$ find the length of each side of the triangle.b. Express the perimeter of the triangle in simplest radical form.

a) $\sqrt{40}, \sqrt{40}, \sqrt{10}$b) 5$\sqrt{10}$

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Chapter 3

REAL NUMBERS AND RADICALS

Section 8

Solving Radical Equations

Whole which of Numbers

Fractions and Mixed Numbers

Decimals

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for triangle to be considered a right triangle. If side see is the high pot news in the protagonist there, Um, a squared plus B squared equals C squared should prove to be true. So we're given a is the square root of 21 B is six and see is the square root of 57 we can done square The square root of 21 which would just be 21 was square six, which is 36 in square, the square root of 57 which would be 57. We add 36 21 which would be 57. That does, in fact equal 57. So yes, this is a right triangle.

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