In triangle $P Q R$ shown in Fig. 12.14, find the lengths of $P Q$ and $P R$. $\tan 38^{\circ}=\frac{P Q}{Q R}=\frac{P Q}{7.5}$
hence $\quad P Q=7.5 \tan 38^{\circ}=7.5(0.7813)$
$=5.860 \mathrm{~cm}$
$\cos 38^{\circ}=\frac{Q R}{P R}=\frac{7.5}{P R}$
hence $\quad P R=\frac{7.5}{\cos 38^{\circ}}=\frac{7.5}{0.7880}=9.518 \mathrm{~cm}$