In which of the following case, the value of Kp is less than Kc ? (a) N2+O2 ⇌2 NO (b) H2+Cl2 ⇌2

Name: Problem 48, Chapter 7: A Complete Resource Book in Chemistry for JEE Main 2018
Uploaded: 2021-10-13T07:18:14-08:00
Duration: 2 min 51 s
Channel: Preeti Kumari
Description: In which of the following case, the value of Kp is less than Kc ? (a) N2+O2 ⇌2 NO (b) H2+Cl2 ⇌2 HCl (c) 2 SO2+O2 ⇌2 SO3 (d) PCl5 ⇌PCl3+Cl2

step 1 In this problem, we have to find out for which of the following reaction the value of KP is less

Question

In which of the following case, the value of $K_p$ is less than $\mathrm{K}_{\mathrm{c}}$ ? (a) $\mathrm{N}_2+\mathrm{O}_2 \rightleftharpoons 2 \mathrm{NO}$ (b) $\mathrm{H}_2+\mathrm{Cl}_2 \rightleftharpoons 2 \mathrm{HCl}$ (c) $2 \mathrm{SO}_2+\mathrm{O}_2 \rightleftharpoons 2 \mathrm{SO}_3$ (d) $\mathrm{PCl}_5 \rightleftharpoons \mathrm{PCl}_3+\mathrm{Cl}_2$

   In which of the following case, the value of $K_p$ is less than $\mathrm{K}_{\mathrm{c}}$ ?
(a) $\mathrm{N}_2+\mathrm{O}_2 \rightleftharpoons 2 \mathrm{NO}$
(b) $\mathrm{H}_2+\mathrm{Cl}_2 \rightleftharpoons 2 \mathrm{HCl}$
(c) $2 \mathrm{SO}_2+\mathrm{O}_2 \rightleftharpoons 2 \mathrm{SO}_3$
(d) $\mathrm{PCl}_5 \rightleftharpoons \mathrm{PCl}_3+\mathrm{Cl}_2$

A Complete Resource Book in Chemistry for JEE Main 2018

A.K. Singhal 3rd Edition

Chapter 7, Problem 48

Instant Answer

Solved by Expert Preeti Kumari

10/13/2021

Step 1

The equilibrium constants $ K_p $ and $ K_c $ are related by the equation: \[ K_p = K_c (RT)^{\Delta n} \] where $ \Delta n $ is the change in the number of moles of gas (moles of products - moles of reactants), $ R $ is the ideal gas constant, and $ T $ Show more…

Show all steps

Thanks for your feedback!

In which of the following case, the value of $K_p$ is less than $\mathrm{K}_{\mathrm{c}}$ ? (a) $\mathrm{N}_2+\mathrm{O}_2 \rightleftharpoons 2 \mathrm{NO}$ (b) $\mathrm{H}_2+\mathrm{Cl}_2 \rightleftharpoons 2 \mathrm{HCl}$ (c) $2 \mathrm{SO}_2+\mathrm{O}_2 \rightleftharpoons 2 \mathrm{SO}_3$ (d) $\mathrm{PCl}_5 \rightleftharpoons \mathrm{PCl}_3+\mathrm{Cl}_2$

Play audio

Feedback

Preeti Kumari and 61 other educators are ready to help you.

Ask a new question

Labs

Want to see this concept in action?

NEW

Explore this concept interactively to see how it behaves as you change inputs.

View Labs

Key Concepts

Equilibrium Constants (Kp and Kc)

Kp and Kc are two ways to express the equilibrium constant of a chemical reaction. Kc is defined in terms of the molar concentrations of reactants and products, while Kp is defined using the partial pressures of the gaseous species involved. The two constants are related by the equation Kp = Kc(RT)^(?n), where R is the gas constant, T is the temperature in Kelvin, and ?n is the change in moles of gas between the reactants and products.

Change in Moles of Gas (?n)

?n represents the difference between the total moles of gaseous products and the total moles of gaseous reactants. This quantity is crucial when converting between Kp and Kc because it determines the exponent in the relationship Kp = Kc(RT)^(?n). When ?n is negative, the factor (RT)^(?n) becomes less than one, leading to a situation where Kp is less than Kc, assuming RT is greater than one in absolute value.

Please give Ace some feedback