Question
In young's double slit experiment the phase difference is constant between two sources is $(\pi / 2)$. The intensity at a point equidistant from the slits in terms of max. intensity $\mathrm{I}_{0}$ is(A) $3 \mathrm{I}_{0}$(B) $\left(\mathrm{I}_{0} / 2\right)$(C) I_{0 }(D) $\left(3 \mathrm{I}_{0} / 4\right)$
Step 1
Step 1: In Young's double slit experiment, the intensity at a point is given by the formula $I = I_0 \cos^2(\phi/2)$, where $\phi$ is the phase difference between the two sources. Show more…
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