Question

Indicate the total number of (a) $p$ electrons in $\mathrm{N}(Z=7)$, (b) $s$ electrons in $\mathrm{Si}(Z=14)$, and (c) $3 d$ electrons in $\mathrm{S}(Z=16)$.

   Indicate the total number of (a) $p$ electrons in $\mathrm{N}(Z=7)$, (b) $s$ electrons in $\mathrm{Si}(Z=14)$, and (c) $3 d$ electrons in $\mathrm{S}(Z=16)$.
 
Chemistry
Chemistry
Raymond Chang, Jason… 14th Edition
Chapter 7, Problem 66 ↓
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Indicate the total number of (a) $p$ electrons in $\mathrm{N}(Z=7)$, (b) $s$ electrons in $\mathrm{Si}(Z=14)$, and (c) $3 d$ electrons in $\mathrm{S}(Z=16)$.
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Transcript

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00:01 Okay, so we need to figure out how many specific types of electrons are in different atoms.
00:10 So the first part they ask is how many p electrons are in nitrogen.
00:15 All right, so we need to write out its electron configuration first.
00:20 So for nitrogen, we know that its atomic number is 7.
00:23 So we can write that as z is equal to 7.
00:27 And since we know that nitrogen is in its neutral state that its atomic number of protons, the 7 will be equal to its number of electrons, which is 7 as well.
00:39 So we need to have 7 electrons in our electron configuration.
00:45 So we know we start with the lowest energy orbital.
00:49 So this is 1s.
00:51 All right.
00:52 We have 2 in there.
00:54 So we have 5 left.
00:55 Then we're going to go to the second lowest, which is.
00:58 2s.
01:00 We have two electrons in there because we know we can only hold two electrons in each s orbital.
01:06 Now we have to move on to the third lowest, which is going to be 2p.
01:12 All right.
01:12 Since we have we need seven, we have four already.
01:16 We're just going to go ahead and fill up three.
01:20 The p orbital, so each of these suborbital are going to have one electron in them.
01:26 So this would be, total would be three total p orbitals or electrons in p subshells or p orbitals.
01:36 So now we're looking for s electrons in silicon.
01:41 So silicon has an atomic number of 14.
01:47 And since we know that it's neutral, we know that there must be 14 electrons as well.
01:53 So we can go ahead and say 1s2.
01:59 2s2...
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