00:01
All right, so even though this question doesn't ask for a lewis structure, it's going to make it a lot easier to see what's going on here.
00:08
So i'm going to start out with our beryllium bonded to two bromines.
00:18
Now beryllium doesn't have to fill its octet.
00:21
It's a metal, and it's also far enough on the left of the periodic table that it can't really fill its octet.
00:31
So this is what our lewis structure looks like.
00:36
Borrelium is going to form two bonds, which means it has to use an sp orbital.
00:44
It would be sp3 if these alone -o -electron pairs were filled, but since they're not, the p -orbitals are just empty.
00:52
While the bromine is going to have sp3 orbitals, because its lone -o -electron pairs are actually filled, it needs to put those into orbitals.
01:04
And if you want to be even more specific, these are the two s and the three sp3s.
01:14
For mercury chloride, it's going to look very similar to this on the outside...