00:01
So, mendelief proposed that the formula for indium oxide was in203.
00:09
He saw that because he saw that for every single one gram of oxygen, he had 4 .784 grams of indium.
00:22
And i'll put the sign for indian, which is just i .n.
00:26
Now, how do you get that number? well, if i go on the periodic table and i look at indium, i'll find that the molar mass or atomic mass of indium is 114 .82.
00:41
114 .82, and there was two of them, right? so if we put that into our calculator, we can figure out what the relative proportion of indium was.
00:52
So we had 114 .82 times 2.
00:57
So in total, let's say we're just looking at this molecule.
01:00
We're looking at just one of them.
01:02
We're trying to figure out atomic mass units.
01:03
We'd have 229 .64.
01:07
Let's say, let's use amus, atomic mass units of indium.
01:14
And we'd also have about 48, so oxygen 16 times three of them right there.
01:20
So be 48 amus of oxygen...