00:01
The magnetic field inside a solenoid is b is equal to mu knot n times i over l, where n is the number of turns in the coil, i is the current through the coil, and l is the length of the coil.
00:14
And we also know that the definition of self -inductance tells us that l is equal to the number of turns in the coil in times the flux through each coil, phi, divided by the current through the coil, i.
00:31
And the flux to each tail of the coil, phi b, is defined as new not times n times a times the current i over l, where it is the cross -sectional area.
00:56
So if we combine these expressions, we can rewrite l as follows.
01:04
So l we know is n times phi b over i.
01:14
And if we substitute our expression for phi, we get that l, the inductors, the inductors, of the coil is equal to mu not times n squared and a all divided by l.
01:27
As you can see the current i disappears and hence the inductance does not explicitly depend on the current.
01:36
So now that we have an expression for the inductance, we can calculate the inductance for these given values.
01:45
In part b, but first let's calculate the cross -sectional area.
01:50
So the cross -sectional area of the coil, we assume it's circular, is equal to pi r squared...