00:01
Part a of the given problem, the electric field is, electric force rather, is responsible for the motion of the drop between the plates.
00:09
So let's say here is a drop between these two plates.
00:13
Then we can write the force will be equal to qe, electric force, is equal to mass time acceleration of the drop.
00:24
From here, q will be m .a.
00:26
Divided by e, where q is the charge of the ink drop, and m is its mass, e is the electric field between the plates.
00:40
So we need to find the acceleration of a drop.
00:43
The drop deflects at the distance of x is equal to 0 .02 meter, with the speed v is equal to 50 meter per second.
00:53
So the time taken to travel this distance will be t is equal to x divided by v, which is 0 .02 divided by 50.
01:02
This gives us 4 times 10 to the power minus 4 seconds.
01:08
Then we can find acceleration from the newton's law of motion.
01:14
It says the distance d travel will be initial velocity times t plus 1 over 2 a t square.
01:22
From here initial velocity is 0, so we can just solve for acceleration.
01:27
So the exclamation will be a 2d divided by t square...