Question
$\int \frac{\cos 8 x-\cos 7 x}{1+2 \cos 5 x} d x$ is(a) $\frac{\sin 3 x}{3}-\frac{\sin 2 x}{2}+C$(b) $\frac{\sin 3 x}{3}+\frac{\sin 2 x}{2}+C$(c) $\frac{\sin 2 x}{2}-\frac{\sin 3 x}{3}+C$(d) $\frac{\cos 3 x}{3}-\frac{\cos 2 x}{2}+C$
Step 1
We can rewrite this as $\int \frac{\cos 8 x-\cos 7 x}{1+2 \cos 5 x} \cdot \frac{2 \sin 5x}{2 \sin 5x} dx$. Show more…
Show all steps
Your feedback will help us improve your experience
Naman Kumar and 98 other Calculus 2 / BC educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
$\int \frac{\cos 7 x-\cos 8 x}{1+2 \cos 5 x} d x=$ (A) $\frac{\sin 2 x}{2}+\frac{\sin 3 x}{3}+c$ (B) $-\frac{\sin 2 x}{2}-\frac{\sin 3 x}{3}+c$ (C) $\frac{\sin 2 x}{2}-\frac{\sin 3 x}{3}+c$ (D) none of these.
$\int \frac{\cos x-\sin x}{\sqrt{8-\sin 2 x}} d x$ is equal to (A) $\sin ^{-1}(\sin x+\cos x)+c$ (B) $\sin ^{-1}\left[\frac{1}{3}(\sin x+\cos x)\right]+c$ (C) $\cos ^{-1}(\sin x+\cos x)+c$ (D) none of these
If $\int[(2 \sin x+\cos x) /(7 \sin x-5 \cos x)] d x$ $=a x+b \log |7 \sin x-5 \cos x|+c$ then $a-b=$ (a) $(4 / 37)$ (b) $-(4 / 37)$ (c) $(8 / 37)$ (d) $-(8 / 37)$
Transcript
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD