Question
$\int \frac{x^{4}-1}{x^{2} \sqrt{x^{4}+x^{2}+1}} d x=$(A) $\frac{\sqrt{x^{4}+x^{2}+1}}{x}+C$(B) $\frac{x}{\sqrt{x^{4}+x^{2}+1}}+C$(C) $-\frac{\sqrt{x^{4}+x^{2}+1}}{x}+C$(D) none of these
Step 1
Step 1: First, we rewrite the integral as follows: \[\int \frac{x^{4}-1}{x^{2} \sqrt{x^{4}+x^{2}+1}} d x = \int \frac{x^{2}(x^{2}-1)}{x^{2} \sqrt{x^{4}+x^{2}+1}} d x\] Show more…
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