integrate-each-of-the-given-expressions-int-5-x4-d-x-3

Question

Integrate each of the given expressions.
$$\int 5 x^{4} d x$$

Dwijendra Rao · Accepted Answer

Hello Friends. We have to integrate this expression. It is given that in the question In 2005 into extra the power four new york&#x27;s so we can write it like this. Five into integration of X. To the power four dx. Integration of extra depart affordability, Extra the bar four plus Wannabovorn four plus one political insurgency. So this will be cost 25 and two Have to depart five upon five. Let&#x27;s watch and see. So the indication of five Extra d. 4 4 The X. will because two extra the par five plus constant C. So this will be there. Answer I hope you understood.

Sid Wan · Answer

Columbo twenty four. We have integral explosive force sac next to firsthand X to the fifth D X. It looks complicated by Don&#x27;t worry. Let&#x27;s take you to the extra. The fifth. The year was five x to the force, The eggs. And we know. Okay, we&#x27;re around, Is us this God is one over five T yu Second, you tange. You you And we know this Integral is just Ah, sank off you right back off, you pussy. You were going Quarter five, sack exclusive. That&#x27;s good.

Aishwarya Krishnakumar · Answer

of her problem. Seven, we are asked to find this indefinite integral. And to do this, we&#x27;re gonna use U substitution. And we&#x27;re gonna what you equal, whatever is inside the current disease. So this case would be six packs squared was 15 X. Now we take the derivative off both sides. Do you? Because 12 ax instead, the derivative of this waas 15 drove explodes. 15 in this whole thing terms D x no, you can like. You can simplify this divided all by three. Before I it was fine Times three. And this works out because we have a four eggs plus five over here and affords plus five over here. So now you just do the u substitution. So this equals in a girl. Uh, so to do that you it would be one over you to the third power. Since we&#x27;re bugging in this you instead of the six x squared plus 15 it&#x27;s And instead of the forex puts five, we would what do you which is for exposed by three Tietz? However, since we have an extra three, we would have to divide and we can take the Constance out, which is one over three and we leave the U to the negative three inside. And now it becomes easy to find the integral. You would just add one. So it would be you to the negative too. We&#x27;re one over. I mean, just negative too. And don&#x27;t forget, plus C. And you can&#x27;t leave the answer with a you. So you have to plug in the value you chose for you. In this case, you chose six X squared. What&#x27;s 15 x Chose that for you. Plug it in and this is the final.

Alex Johnson · Answer

in this problem, we&#x27;re gonna find the anti derivative of X to the fifth. Won&#x27;t live by Cho. Tangent of X to the sixth is the first step is that I&#x27;m gonna convert this into signing coastline. So have X to the fifth multiplied by co sign of ext the sixth over Sign next to the sixth. Next, we&#x27;re gonna turn this into a U substitution. So let&#x27;s let you equal sign of X to the sixth, which would give us D&#x27;You equal to co sign of X to the sixth multiplied by five. Excuse me, six extra 50. Now the excellent fifth is showing up in the original, but not the six. So let&#x27;s move the six over by division and we get X to the fifth co sign of corny X to the sixth. And we do see that all of those d&#x27;you values air now showing up in the original. So our new integral will be 1/6 of the integral of one over you, do you, which gives us 1/6 of the natural log of the absolute value of you plus C. And if we convert this back in terms of X, we get 1/6 the natural log of the absolute value of sign of X to the sixth plus c

Linh Vu · Answer

it is question. Religion file Indefinite Integral. Off the X power to oppress far. Thanks. Minus five. Gee, thanks. Hey, recording the power row fall expert and the banks will echo Judah. Expel Ambrus one over an endless one plus c using this formula here the first time we can get in coaching. Exploratory Over three. The second term that comes, Stand far. Stay the same. You have expert, you overt you. And for the constant five, we have touched the X next to it now, plus a constant C in with some refined. And then we get called Ju Ju X squared minus five x plus c.

Donald Yeh · Answer

All right, So we&#x27;re going to the Inter Girl. Um, basically the integral from 0 to 5 of the function x the fourth times y plus why t x and I know what you&#x27;re thinking. It&#x27;s a little confusing efforts because you see two variables, but there&#x27;s no, like double integral. So don&#x27;t be worried because, um, you&#x27;re not trying to find a numerical answer in this poem, but more of a you&#x27;re gonna have variables in your answering them, so don&#x27;t worry about it too much. So let&#x27;s start. Um, so I&#x27;m just gonna factor out the why on this is because we have a D accident roll, meaning we&#x27;re integrating respect, Teoh X. So every other variable is treated as a constant. So by factoring out this, why I can then move this wide to the outside of the integral, as if they were a constant, because we are integrators by two. Thanks. Okay, so now I have this integral. And now what we can dio is just used the reverse of the power rule in order to integrate Excellent fourth. So we just add one to the exponent and then divide by that new exponents. So excellent fifth Divide by five and then plus X. And we want to evaluate this from 0 to 5. So just playing in, um, we get five to the fifth over five, plus five, and then we want to subtract the second component, Um, which should just be a zero plus zero. Okay, It&#x27;s gonna be equal to just gonna simplify that. Five to the fourth, because five to the fifth of I 55 to the fourth plus five we have. Why times five to the fourth is 6 25 on at five. So our final answer should be 6 30 times. Why?

Problem

Integrate each of the given expressions. $$\int 6…

Problem 6 Easy Difficulty

Integrate each of the given expressions.
$$\int 5 x^{4} d x$$

Answer

$x^{3}+C$

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Allyn J. Washington, Richard S. Evans

Basic Technical Mathematics with Calculus

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$x^{3}+C$

Basic Technical Mathematics with Calculus

Catherine R.

Kayleah T.

Samuel H.

Joseph L.

Precalculus Review - Intro

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Allyn J. Washington, Richard S. EvansBasic Technical Mathematics with Calculus

Catherine R.

Kayleah T.

Samuel H.

Joseph L.

Allyn J. Washington, Richard S. Evans

Basic Technical Mathematics with Calculus