Question
Integrate $G(x, y, z)=z-x$ over the portion of the graph of $z=x+y^{2}$ above the triangle in the $x y$ -plane having vertices (0, 0,0)$,(1,1,0),$ and $(0,1,0) .$ (See accompanying figure.)
Step 1
We want to integrate $G$ over the portion of the surface above the triangle in the $xy$-plane with vertices (0,0,0), (1,1,0), and (0,1,0). First, we need to find the limits of integration for $x$ and $y$. The triangle in the $xy$-plane is bounded by the lines $x Show more…
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Integrate $G(x, y, z)=z-x$ over the portion of the graph of $z=x+y^{2}$ above the triangle in the $x y$ -plane having vertices $(0,0,0),(1,1,0),$ and $(0,1,0) .$ (See accompanying figure.)
Integrals and Vector Fields
Surface Integrals
Integrate $G(x, y, z)=z-x$ over the portion of the graph of $z=x+y^{2}$ above the triangle in the $x y$ -plane having vertices $(0,0,0),(1,1,0),$ and $(0,1,0) .$ (See accompanying figure.) (FIGURE CAN'T COPY).
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