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Problem

Integrate the functions. $$ \sqrt{a x+b} $$

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Problem 1 Problem 2 Problem 3 Problem 4 Problem 5 Problem 6 Problem 7 Problem 8 Problem 9 Problem 10 Problem 11 Problem 12 Problem 13 Problem 14 Problem 15 Problem 16 Problem 17 Problem 18 Problem 19 Problem 20 Problem 21 Problem 22 Problem 23 Problem 24 Problem 25 Problem 26 Problem 27 Problem 28 Problem 29 Problem 30 Problem 31 Problem 32 Problem 33 Problem 34 Problem 35 Problem 36 Problem 37 Problem 38 Problem 39

Problem 5 Easy Difficulty

Integrate the functions.
$$
\sin (a x+b) \cos (a x+b)
$$

Answer

More Answers

01:34

Suman Saurav T.

Related Courses

Calculus 2 / BC

NCERT Class 12 Part 2 - Math

Chapter 7

Integrals

Section 2

Integration as an Inverse Process of Differentiation

Related Topics

Integration Techniques

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Integration Techniques - Intro

In mathematics, integratio…

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In mathematics, a techniqu…

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01:04

Find the indefinite integr…

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…

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…

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Watch More Solved Questions in Chapter 7

Problem 1
Problem 2
Problem 3
Problem 4
Problem 5
Problem 6
Problem 7
Problem 8
Problem 9
Problem 10
Problem 11
Problem 12
Problem 13
Problem 14
Problem 15
Problem 16
Problem 17
Problem 18
Problem 19
Problem 20
Problem 21
Problem 22
Problem 23
Problem 24
Problem 25
Problem 26
Problem 27
Problem 28
Problem 29
Problem 30
Problem 31
Problem 32
Problem 33
Problem 34
Problem 35
Problem 36
Problem 37
Problem 38
Problem 39

Video Transcript

in this question we are required to find the integral of sine A. X plus B multiplied with because A X plus B. So let us write the it's here and the end eagles in here. We will meet the substitution sign A X plus B is equal to P. Now differentiating both sides we get of course A X plus B multiplied with the in different shell of A X. Which will be A. The eggs will be equal to B. P. So from here we can see that cause A X plus B. The X is equal to D. T. Divided by eight. Making the substitution in the integral. We right in the runoff B. Bp and we can write divided by A. Since it is a constant we can take it outside and right integral of DDT. This will be equal to one divided by a P square divided by two plus a constant of integration capital C. Now let us substitute the value of the back in this expression. To get the final answer as sign square A X plus B divided by two E. Plus capital C. This will be the final answer.

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Pawan K. Jain

NCERT Class 12 Part 2 - Math

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