Question
Integrate the given function over the given surface.$H(x, y, z)=y z,$ over the part of the sphere $x^{2}+y^{2}+z^{2}=4$ that lies above the cone $z=\sqrt{x^{2}+y^{2}}$
Step 1
The sphere is given by the equation \(x^2 + y^2 + z^2 = 4\), which is a sphere of radius 2 centered at the origin. The cone is given by \(z = \sqrt{x^2 + y^2}\), which is a right circular cone with its vertex at the origin and opening upwards. Show more…
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Integrate the given function over the given surface. \begin{equation}\begin{array}{l}{\text { Spherical cap } H(x, y, z)=y z, \text { over the part of the sphere }} \\ {x^{2}+y^{2}+z^{2}=4 \text { that lies above the cone } z=\sqrt{x^{2}+y^{2}}}\end{array}\end{equation}
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Integrate the given function over the given surface. Spherical cap $H(x, y, z)=y z,$ over the part of the sphere $x^{2}+y^{2}+z^{2}=4$ that lies above the cone $z=\sqrt{x^{2}+y^{2}}$.
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