00:01
For part a, we are going to draw the loose structures of these compounds.
00:05
So the first one is if3.
00:07
You will have one iodine that is bound to three fluorine molecules, and it will have two lone pairs of electrons.
00:20
Next for if4 minus, central iodine again, that is bound to four fluorines and has two lone pairs of electrons, and that negative 1 charge is on the iodine.
00:36
For i have 5, we will have iodine bonded to 5 fluorines and 1 lone pair of electrons.
00:48
For i have 6 minus, the iodine is bonded to 6 fluorines and has one lone pair of electrons.
01:02
The negative 1 charge is on the iodine.
01:05
And lastly, i have 7 is iodine bonded to seven forings.
01:20
For part b of this question, we are asked to give the hybridization of the iodines.
01:31
So the first iodine has three bonds and two lone pairs.
01:35
So that means it has five regions of electron density.
01:38
So it is sp3d hybridized.
01:43
For if4 minus, there's two lone pairs and four bonds.
01:47
So there's six regions of electron density.
01:49
So the hybridization of the iodine is sp3d2...