00:01
So in this problem, it says iodine azide ion3 adds to alkenes by an electrophilic mechanism similar to that of bromine.
00:13
If a monosubstitute alkenes, it's just one beautine, is used, only one product result.
00:23
So we're going to add the loan pairs to ion3 and draw second resonance form, calculate the formal charges, determine the polarity of the ion3 bond, and propose a mechanism using curved arrows to show electron.
00:37
So we know that we need an octet around each of these atoms.
00:46
So when we add in the known pairs of electrons, each bond represents two electrons.
00:55
And we can form double bonds between the nitrogen.
01:00
So we need to add three lone pairs to the iodine, one lone pair to the nitrogen, and then two lone pairs to the nitrogen on the right.
01:08
Formal charge is equal to a number of valence electrons, minus number of non -bonding minus number of bonds.
01:16
So for iodine, we have seven balanced electron minus six non -bonding and one bond.
01:24
And then we get zero...