Ionization energy is the energy required to remove an...

Ionization energy is the energy required to remove an electron from an atom in the gas phase. The ionization energy of gold is $890.1 \mathrm{~kJ} / \mathrm{mol}$. Is light with a wavelength of $225 \mathrm{~nm}$ capable of ionizing a gold atom (removing an electron) in the gas phase?

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Key Concepts

Photoionization

Photoionization refers to the process in which an electron is removed from an atom or molecule as a result of absorption of a photon with energy equal to or greater than the ionization energy. This concept integrates the understanding of both ionization energy and photon energy in screening the capability of light to ionize atoms.

Energy-Wavelength Relationship

The energy-wavelength relationship indicates that the energy of a photon is inversely proportional to its wavelength. This principle is important when determining whether light of a specific wavelength has sufficient energy to induce processes such as electron ionization.

Ionization Energy

Ionization energy is the amount of energy required to remove an electron from an atom in the gas phase. It is a fundamental property of each element that reflects how tightly electrons are bound to the nucleus, influencing chemical behavior and reactivity.

Photon Energy

Photon energy is the energy that a photon carries, which depends on its wavelength or frequency, as described by the equation E = hc/?. This concept is crucial for understanding how light interacts with matter, particularly in processes involving energy transfer.

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