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Problem 27

Iron reacts slowly with oxygen and water to form a compound commonly called rust $\left(\mathrm{Fe}_{2} \mathrm{O}_{3} \cdot 4 \mathrm{H}_{2} \mathrm{O}\right) .$ For 45.2 $\mathrm{kg}$ of rust, calculate (a) moles of compound; (b) moles of $\mathrm{Fe}_{2} \mathrm{O}_{3} ;(\mathrm{c})$ grams of $\mathrm{Fe} .$

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Chapter 3
Stoichiometry of Formulas and Equations
CHEMISTRY: The Molecular Nature of Matter and Change 2016

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