00:01
High in the given problem the number of turns in the coil is given as n is equal to hundred diameter of this coil is given as 6 .0 meter so its radius r will be given as half of the diameter means 6 .0 meter by 2 means this is r is equal to 3 .0 meter, the current passing through this coil is i is equal to 5 .0 ampere.
00:49
Now in the first part of the problem, we have to find the magnetic field produced and the center of this coil.
00:57
So magnetic field produced at the center of the coil is given as b is equal to.
01:16
To mu not n i by 2 r.
01:23
Here for mu not this is 4 pi into 10 dash per minus 7 tesla meter per ampier into for the number of turns this is 100 for current this is 5 amper divided by 2 multiplied by radius which is 3 .0 meter.
01:45
So finally, this magnetic field here comes out to be 10 .5 into 10 dash per minus 5 tesla, which becomes the answer for the first part of this problem.
02:08
In the second part of the problem, the direction of flow of the water, here at the center of this coil, the direction of magnetic field, which we have just found, its direction here is given as vertically downward, and the water is flowing east.
02:38
So, if we consider the directions to be north, south, and east, west to be here, the direction of the direction of, the motion of the positive ions will be same as that of the direction of flow of the water.
03:02
Means this is v, the velocity vector.
03:06
Here this is b, the magnetic field vector.
03:10
And here, using the expression for the magnetic lawrence force experienced by the charge particles moving in magnetic field, that is given as f, is equal to q into v cross b...