Question
Is it possible for a $^{12}_{6} \mathrm{C}(12.000000 \mathrm{u})$ nucleus to spontaneously decay into three alpha particles? Explain.
Step 1
We need to determine if a carbon-12 nucleus (\(^{12}_{6} \mathrm{C}\)) can spontaneously decay into three alpha particles. An alpha particle is a helium-4 nucleus (\(^{4}_{2} \mathrm{He}\)). Show more…
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The radionuclide ${ }^{232} \mathrm{U}$ alpha-decaps into ${ }^{228}$ Th. $(a)$ Find the energy released in the decay, (b) is it possible for ${ }^{232} \mathrm{U}$ to decay into ${ }^{231} \mathrm{U}$ by emituing a neutron? $(c)$ is it possible for ${ }^{232} \mathrm{U}$ to decay into ${ }^{231} \mathrm{~Pa}$ by emiting a proton? The atomic masses of ${ }^{231} \mathrm{U}$ and ${ }^{231} \mathrm{~Pa}$ are respectively $231.036270 \mathrm{u}$ and $231.035880 \mathrm{u} .$
(III) (a) Show that the nucleus $^{8}_{4}$Be (mass $=$ 8.005305 u) is unstable and will decay into two $\alpha$ particles. ($b$) Is $^{12}_{6}$C stable against decay into three $\alpha$ particles? Show why or why not.
NUCLEAR PHYSICS AND RADIOACTIVITY
Binding Energy and Nuclear Forces
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