Is the value of $P(x, y)$ sometimes, always, or never greater than the value of $C(x, y) ?$ (Assume $x \neq 1, y \neq 1$, and $x \neq y$.)
All right, So we're asked to compare, um, the permutation of excuse why and in the combination of excuse. And so in this case, the permutation is always greater than the combination. For example, if we had the permutation of five choose three. That's just five times for times three comes two times one, which is going to be 120. But if we have the combination of five, choose three. Then we have to take that 1 20 and divide out the three times two times one which is going to give us 1 20 divided by six or simply 20. Um, and so you're confident permutation is always created in your combination.