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Is there a point on the curve in Exercise 45 where the

osculating plane is parallel to the plane $x+y+z=1 ?$

[Note: You will need a CAS for differentiating, for sim-

plifying, and for computing a cross product.]

$$

x+y+z=1

$$

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Campbell University

Harvey Mudd College

Baylor University

University of Michigan - Ann Arbor

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