Isoflurane, shown here, is a common inhalation anesthetic. Write its molecular formula and calcu

step 1 We have given information. There are three carbon atoms, five fluorine atoms, two hydrogen atoms

Isoflurane, shown here, is a common inhalation anesthetic....

Key Concepts

Molecular Formula

The molecular formula represents the types and numbers of atoms present in a molecule by using element symbols and subscript numbers. It provides a concise way to show the composition of a chemical compound including the proportions of each element.

Molar Mass Calculation

Calculating the molar mass involves summing the atomic masses of all atoms indicated by the molecular formula, which yields the total mass of one mole of the compound. This is an essential step in further quantitative analyses, such as determining percent composition by mass.

Percent Composition by Mass

Percent composition by mass is a calculation that shows what percentage each element contributes to the total mass of a compound. By dividing the mass of each element (from its atomic weight multiplied by the number of atoms in the formula) by the total molar mass and multiplying by 100, one determines the mass percentage of that element.

Transcript

00:03 We have given information.

00:08 There are three carbon atoms, five fluorine atoms, two hydrogen atoms, and one chlorine atom.

00:42 Therefore, the molecular formula of isofluorine, isofluorine, fluorine is c3 f5 oh5 cl and we have to find the percent composition by mass so the molar mass of isofluorine is molar mass of isoflorine is equal to three in to molar mass of carbon plus 5 into molar mass of fluorine plus molar mass of oxygen plus 2 into molar mass of hydrogen plus molar mass of chlorine is equal to 3 into molar mass of carbon is 12 .01 1 gram per mole plus 5 into molar mass of fluorine is 18 .998 gram per mole plus molar mass of oxygen is 15.

03:42 Molar mass of oxygen is 15 .99 .9 .9 gram per mole plus 2 into molar mass of hydrogen is 1 .00 .000 0 .08 gram per mole plus molar mass of chlorine is 35 .43 gram per mole is equal to 184 .491 gram per mole.

04:35 Now we can find the mass present composition.

04:51 So mass percent of carbon in a compound is equal to 3 into molar mass of carbon divided by molar mass of the compound isopurane.

05:17 Isoflorine is c3 f5 -oh2cl into 100 %.

05:36 Is equal to 3 into molar mass of carbon is 12 .11 gram per mole divided by molar mass of isoflorine is 184 .49 gram per mole is equal to the calculated percent of carbon is 19 .53.

06:19 Ground per mole can sell with ground per mole and the value is 19 .53%.

06:36 And percent of fluorine in a compound is equal to mass of fluorine divided by, and molar mass of fluorine divided by molar mass of isoflorine c3 f5, of oh2 cl in 200 % is equal to molar mass of fluorine is 18 .998 gram per mole divided by molar mass of isoflorine is 18 .491 per mole...

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