00:01
So the way this would work is what we're really trying to compare is is the oxygen that's right here at the end of the reaction coming from here or here.
00:12
And so what we would do is we would pick one of these two reactants and have it created with labeled oxygen.
00:20
So i'll write, when i refer this labeled auction, i'll write it in red.
00:25
So it's 18 as its atomic mass.
00:28
And so an example could be that we would label all the oxygens in the methanol here as the 18 version.
00:38
Okay.
00:38
And then there are two options really.
00:41
Either the reaction goes on to give us ch3 -o2 -ch3 and then water without the labeled one.
00:55
Or the opposite result would be that we would keep, have the, in, the ester, which is this right here, we would have the non -labeled version, and then in the water, we would have the labeled version...
