0:00
All right.
00:03
This problem is talking about heights of 20 to 29 year old females, and their mean height is 64 .1 inches, and the standard deviation is 2 .8 inches.
00:20
All right? so on all these problems, we are going to be using the normal distribution formula using z values.
00:31
That is the numbers we plug in is going to be a minus mu over the standard deviation.
00:41
So part a want to know about the percentile of a 60 inch tall girl.
00:49
All right.
00:51
So plug into the formula.
00:54
60 minus 64 .1 over 2 .8.
01:01
So that is negative 4 .1 over 2 .8, which gives you a z value of negative 1 .46.
01:14
All right.
01:15
Now, using a table of z values, i can look up negative 1 .46 and find that this is a percentage of 7 .22.
01:28
So a girl who is 60 inches tall is in the seventh percentile.
01:32
All right.
01:37
Letter b wants to know the same thing about a 70 inch tall girl.
01:41
All right.
01:49
We plugged in 70.
01:51
So we get 5 .9 divided by 2 .8.
01:56
We have a z value of 2 .1.
02:02
2 .11.
02:03
All right...