00:01
To solve the problem in which the equation of the curve is given as x over 6 risk to par 3 by 2 plus y over 4 risp by 2 equal to 1 and the line x -cose theta plus y -syn theta equal to p touches the curve.
00:14
That means the line x -cose theta plus y -sign theta equal to p is a tangent to the curve.
00:19
So now first of all for solving this problem we'll be using the fact that cost square a plus sine square a is equivalent to 1.
00:31
Applying the same to the curve equation of the curve will obtain the value of x to be equivalent to 6 times of cause a raised to power of 4 by 3 and the 4 y is equal into 4 times of sine a ratio power 4 by 3 and that parameterized this is the parametric form of the x and y so let us now find this low that is d by d xx of the curve using the parametric form.
01:06
So we'll obtain the following d .y by d a over dx by d a, which is equivalent to minus 2 by 3 times of kosi over sine a raised to the power of 2 by 3.
01:20
Now we'll find the equation of the tangent to the curve at the angle a.
01:29
That is we will be using the following equation which is y minus y not to d .y by dx times x minus x not for finding the equation of the tangent at the angle a.
01:43
So we will substitute the values of y not x not and d by dx to obtain the following that is y minus 4 times of sine a raised to the power of 4 by 3 equated to minus 2 by 3 times of cos a over sine a raised to the power of 2 by 3 times x minus 6 times of 6 times of of cos a raised to the power of 4 by 3...