Question
It takes $2,267 \mathrm{~J}$ of heat to raise the temperature of a $44.5 \mathrm{~g}$ sample of a metal from $33.9^{\circ} \mathrm{C}$ to $288.3^{\circ} \mathrm{C}$. What is the heat capacity of the metal?
Step 1
ΔT = T_final - T_initial ΔT = 288.3°C - 33.9°C ΔT = 254.4°C Show more…
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