k_mathrmsp-for-copperii-hydroxide-mathrmcumathrmoh_2-has-a-value-22-times-10-20-at-25circ-mathrmc-ca

Question

$K_{\mathrm{sp}}$ for copper(II) hydroxide, $\mathrm{Cu}(\mathrm{OH})_{2},$ has a value
$2.2 	imes 10^{-20}$ at $25^{\circ} \mathrm{C}$ . Calculate the solubility of cop$\operatorname{per}(\mathrm{II})$ hydroxide in $\mathrm{mol} / \mathrm{L}$ and $\mathrm{g} / \mathrm{L}$ at $25^{\circ} \mathrm{C}$

Anatole Borisov · Accepted Answer

she&#x27;s questions asking us to look at the reaction of copper too hydroxide dissolving in water. So this is solid and it&#x27;s going to be in equilibrium with copper tube plus and 20 h minus. Is both of these air a quiz? And so we&#x27;re told that we have a Casspi for this reaction which is equal to 2.2. I&#x27;m Centenary of 20th. And so what are we want to do is we want to make a nice table in order to understand what behavior this. So we have the initial the change in the equilibrium. And so remember, solids aren&#x27;t considered in the mass action expression sorting or this house table. But our initial concentration of copper two losses hydroxide mice are chocks at mass hydroxide are both can be effectively zero. So the change stored in the at is going to get plus ax for copper two plus, but plus two acts for the hydroxy time because twice as much is gonna be added because the two co fishing there. So plus two x So we have X and two acts, and now I&#x27;m just scroll down a little bit. I&#x27;m gonna write with the mass action expression should be here in red. Remember, the mass action expression is going to be the products of all the You mean like the product of the concentration of see you two plus times a concentration of O. H. Minus squared. And the reason I get that squared over here is because of the two cola fish. And so oh, plugging when we should have Caspi is gonna be equal to X times two x whole thing squared. And so that equals four x cubed. And as I said before, that&#x27;s going to equal, uh, 2.2 Time center, native 20. If that&#x27;s the case be that&#x27;s given to us, and from there it&#x27;s kind of easy to solve. Rex, um, you just pulled into a calculator and we&#x27;re gonna get that X equals a 1.76 times since the negative seventh. And this a concentration. And we know that because that&#x27;s what it&#x27;s representing here, the concentration to see you two plus. And so we&#x27;re gonna have, um, units of Moeller. And so that actually defines the answer For the first question, it asks us, Where&#x27;s the soluble iti in moles per leader and So since we&#x27;re really losing acts like X is the amount of see you a wage to that can be really dissolved here. So malaria, remember, is most per leader. And so that&#x27;s the Souljah bility that we&#x27;re looking for Next progressed from the scalability and grams was having the most by this number by the molar mass of copper hydroxide so open. We read this 1.76 times. 10 tonight, seventh moles per leader. But we can multiply by 97 point 561 grams per mole and the most will cancel out. And we&#x27;ll get her answer for Ah, what? The scalability is in grams per liter and that&#x27;s gonna be 1.72 Time center native. Fifth grounds for later. That&#x27;s our answer.

Matthew Confer · Answer

The first thing to do in this question is to write out your reaction. So here we have copper one sulfide, so see you to us. Solid will dissolve to two copper plus a quiz plus s to minus Equus. Now we can set up our K equation that says K is equal to your copper plus concentration squared times you&#x27;re s to minus concentration. Now it tells us that the soluble ity of this is 8.5 times 10 to the negative 17th Moeller. No, that means that this is one of two multiplied by two for the copper. Because there&#x27;s a two out here, so we find that K is equal. Thio two times 8.5 times 10 to the negative. 17th squared times 8.5 times 10 to the negative 17th. When you actually worked this through, you will find that your K value is 2.5 times 10 to the negative 48th and that is your final answer.

Anatole Borisov · Answer

So in this question we&#x27;re looking at, um, the dissociation of nickel hydroxide, um, nickel to hydroxide, to be specific, just solid to become the nickel two plus ion and to hydroxide ions, which are both, uh, acquis. I&#x27;m just having a just traded up here so we don&#x27;t take this now, we&#x27;re going to work through this all symbolically and then just plugging numbers is so we&#x27;re gonna do a nice table to represent the, uh, amount of yeah, that we&#x27;re gonna have a nickel and hydroxide adequate. So we have I see initial change in equilibrium. We ignore solids for this. So doesn&#x27;t matter what&#x27;s over here. Initially, we don&#x27;t have effectively zero concentration of either of these that we&#x27;re gonna have a change, which is gonna be plus acts. And plus two X, which comes from the fact that for every single mole of nickel hydroxide that dissolves, we&#x27;re gonna get a mole of nickel and two moles of hydroxide and that Saudi government of X and two X. So in a different color, we&#x27;re gonna write out the mass actions fresh. Now, remember, the mass action expression is equal to the concentrations of the products here And since we&#x27;re ignoring this, we always go in solids. In the mass action expression, there&#x27;s really nothing in our genome air, nothing for the react. So we&#x27;re gonna have nickel two plus times a concentration of hydroxide squared which comes from the coefficient to here. And so if we plug in this X for nickel and two X for hydroxide will get X times two x squared, which equals four. Execute. So this is we&#x27;re trying to find CASS. Be if we can figure out X that fantastic and were given acts just indirectly works hold different color here. We&#x27;re told that we have 0.14 grams of nickel hydroxide. And so if we could figure out how many moles of nickel hydra because we have that much that dissolves in water Actually, Mom, about that we have 0.14 grams of dissolves in water. So what that means is we can figure out how many moles of that that is. Then we can figure out how many moles of nickel hydroxide dissolved in water, which also is you to be equal to the moors of nickel two plus that&#x27;s dissolved in water, which is equal to acts. And so we need to, uh, divide, uh, 12.14 by the molten black lor weight of nickel hydroxide, which is 92.7 grams per mole. And we&#x27;ll get some amount, which is equal to 1.51 times 10 to negative third moles. And that&#x27;s equal to acts like I just described. And so now, if you plug in that value for four execute, you&#x27;ll get that Casspi is equal to 1.3 seven times 10 to the negative eighth, and that&#x27;s our final.

Sisi Gao · Answer

this cross trask us to calculate the soul ability of Cobra qual Rieti impure order because, well, we&#x27;ve already known the chaos. P equals to 1.2 times turn to the inactive six. So we assume there&#x27;s X Moeller Corporation solution than X Square equals to 1.2 times turned to the next team. Six packs equals to 1.1 times turned to the inactive. Three Moeller on before question be if the call right and I are in solution is 0.1 Mueller for if we use the Caspi here and then the concentration of copper Keita is 1.2 times 10 to the minus five Moeller.

Anatole Borisov · Answer

this question here has us looking at PV seal to lead two chloride, which is solid dissolving in water. And it&#x27;s gonna be an equilibrium reaction. So PB two plus acquis and to see l minus quist. And so we&#x27;re told the Moeller soluble ity of this. In other words, we&#x27;re told how many moles of PBC L two will go and become PV two plus and that two moles of CR minus and so were given that information and were asked to find Casspi and then find the soluble iti in terms of grams per leaders. And so our first step is to me to set up a nice table, as we normally do. If these equilibrium problems remember, a solid is ignored because it&#x27;s not part of the mass action expression. So the initial concentration of PB two glass and steel minus is about zero. We have plus acts and plus two X because of the coefficient right there. If this is when you&#x27;re comfortable to go back and do some more ice stable problems, they&#x27;re simpler. I&#x27;m sure gonna get comfortable doing this. So we have X two X and then if we were out the mass action expression. I&#x27;ll do that. I&#x27;m a different color. Caspi is gonna equal to the concentration of lead two plus times a constellation of C O minus squared. And if you start plugging in, we&#x27;ll get that we have X Times two x squared, which equals four x cubed. And so, if we could figure out for what? Exes? Because we&#x27;re looking for Casspi be great. And we actually arguing that directly because we&#x27;re told that the more soluble ity of PB seal to its 3.6 times tense in 90 seconds. Molds for leader, which is also the same missing polarity. And so what this is this is defining the amount A p B C L two that&#x27;s going to become lead and then chlorine also, And so that amount 3.6 times 10 tonight. A second is the value of X that we&#x27;re looking for. And so if you plug this in right here, say that&#x27;s even toe acts. Take four execute. That&#x27;s you&#x27;ll take a S P as we defined up here. And so the answer that you&#x27;ll get is 1.9 times Center that your fourth. There&#x27;s no units on that because that&#x27;s the Caspian. So ask the answer. The first part of the question the next part really is asking is just to take this number 3.6 times. Hence a negative 12th. They&#x27;re negative second most per leader in turn into graphs. Providence. So to do that, you need to multiply by the molecular weight of PTCL two. It&#x27;s his to 78.1 grams per mole. Note that the molds will cancel out. So then we&#x27;re gonna get the answer is about 10 grams per leader as the Celje Bility. In terms of that, those unis that&#x27;s

Problem

$K_{\mathrm{sp}}$ for magnesium carbonate, $\math…

Problem 59 Hard Difficulty

Answer

$K_{s p}=\left[C \sigma^{3+}\right]\left[O H^{-}\right]^{3}$
$K_{s p}=\left[C u^{+}\right]^{2}\left[S^{2-}\right]$

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$K_{s p}=\left[C \sigma^{3+}\right]\left[O H^{-}\right]^{3}$$K_{s p}=\left[C u^{+}\right]^{2}\left[S^{2-}\right]$

Introductory Chemistry

Stephanie C.

Lizabeth T.

Nadia L.

Jacquelin H.

Liquids - Intro

Comparison Of Gases Liquids And Solids

Steven S. Zumdahl, Donald J. DeCosteIntroductory Chemistry

Stephanie C.

Lizabeth T.

Nadia L.

Jacquelin H.

$K_{s p}=\left[C \sigma^{3+}\right]\left[O H^{-}\right]^{3}$
$K_{s p}=\left[C u^{+}\right]^{2}\left[S^{2-}\right]$

Steven S. Zumdahl, Donald J. DeCoste

Introductory Chemistry