k_mathrmsp-for-magnesium-carbonate-mathrmmgco_3-has-a-value-35-times-10-8-at-25circ-mathrmc-calculat

Question

$K_{\mathrm{sp}}$ for magnesium carbonate, $\mathrm{MgCO}_{3},$ has a value $3.5 	imes 10^{-8}$ at $25^{\circ} \mathrm{C}$ . Calculate the solubility of magnesium carbonate in mol $/ \mathrm{L}$ and $\mathrm{g} / \mathrm{L}$ at $25^{\circ} \mathrm{C}$ .

Anatole Borisov · Accepted Answer

this question here is asking us about the association of a museum carbonate, which two solid in water, and this is only partially soluble M G two plus acquis and see a three to minus. And so this could be an equilibrium reaction that is governed by the chaos. P that is given to us, which is 3.5 times cents a day instead of some of this problem were to use a nice table and so initial change equilibrium situation because we always want to a nice table Enough. We&#x27;re getting chaos speeds because we want to understand what&#x27;s happening at equal. But that&#x27;s the case. Be really described. So remember solids are ignored during the mass action expression, so we don&#x27;t care what&#x27;s happening over here on this side. In the initial demonstration of my museum. To possibly carbonate are both zero. The change is gonna be the same for each them plus X plus X, because their story geometrical equal, there&#x27;s a one coefficient. Technically, they&#x27;re both of these, so you deliver and we have accidents. And so remember with them to rewrite the mass action expression. Casspi equals the concentration of magnesium. Two plus times a concentration of carbonate. This is the product of all the concentrations of each of the reactors area to the products over the reactors. But we ignore the solids, and so this equals X squared. Just taking the X from here in the X from there, and we&#x27;re gonna use this plug that in for the task T She was 3.5 times sentiment. And when you solve them, you&#x27;re gonna answer for X, which is equal to 1.87 times 10 sent forth Moller because this is a concentration, as we know from here. And so dash answers our first question because were asked to find the soluble iti in terms of moles per liter. And remember, um, Capital M is actually the same saying moles per liter. And this is defining how much of this magnesium carbonate is going to react to dissolve and become that amount of nine museum two plus and carbonate. And so that answers the first question. Actually, next part the question were intercepted. Multiply this by the molecular weight of magnesium carbonate, so I&#x27;m gonna rewrite it 1.87 time since the negative fourth moles per liter will be multiplied by 84 0.3 grams. Promote. That&#x27;s the mark. Their weight of magnesium carbonate. I just looked it up and most will cancel out. When we do this, we&#x27;re gonna get a final answer, which is? You go to 0.157 grasped her leader, and that&#x27;s our answer.

Anatole Borisov · Answer

this question is here is asking us to look at calcium carbonate dissolving in water, and so that&#x27;s gonna result in cost him two plus a Prius and carbonate ion. Hey, Chris. And so we&#x27;re giving the Caspi that defines how this reaction behaves and that&#x27;s three times sensing it could be really important value for us. There&#x27;s nowhere into a nice table like we always do with these sorts of problems that we have a k value, an equilibrium, constant. We ignore the solids because they don&#x27;t They don&#x27;t play a role in the mass act expression, and I&#x27;ll film this. I stable. We begin with zero. We&#x27;re gonna have a change of plus X because of the common tree Oneto one here. And so it means that equilibrium is gonna have accidents. I&#x27;m gonna right out of the mass action expression, which is a task he is gonna be able to the concentration of calcium to puss times a concentration of carbonate ion. And since we have that right here on equilibrium excess I plugged that in fridge to use will get that cast P equals X scream. And so, taking the Casspi, I&#x27;ll plug that in that we get were given in the problem three times sensitive knife we can easily solve for X and act is going to be equal to 5.47 times 10 to the negative, fifth more. And so what that is that defines the amount of moles per leader, right, that out most per leader of calcium carbonate that dissolves to become either the calcium ion or the carbonate ion. And so, in other words, that&#x27;s that&#x27;s our Moeller soluble ity. But we&#x27;re asked to find the scalability and grams per litre. This is actually really simple conversion we&#x27;re seeing is the molar mass and so going to transfer this over on the right this again 5.47 times. Hence a negative fifth. All right, as moles per liter. This time, if we multiply by 100 point 08 grams per mole which is the molar mass of calcium carbonate, the molds will cancel out, and we&#x27;re gonna get a value in grams per liter. And that&#x27;s going to be our Saul, You bility in those units and the answer we&#x27;re going to get will be 5.4 times 10 to the negative grams per liter. You know what? That&#x27;s what

Sara Ross · Answer

So, given a K S P of magnesium carbonate, that&#x27;s equal to 2.6 times 10 to the negative nine. We&#x27;re asked to calculate the Selya bility of this substance in pure water. So to do so, we first right the equation that represents the soluble ity of this substance. So magnesium carbonate in pure water, we&#x27;ll break into magnesium to plus ions and it will break into carbonate ions so we can write our K S P equation as follows. We can say that the K S P is equal to the concentration of the magnesium to plus times the concentration of the carbonate raised to know coefficients and over no reactant is because that&#x27;s a solid. And we can also say that because there are equal molar ratios of each of these concentrations, they&#x27;re going to be the same. We can essentially substitute both for the same variable in this case s for Celia Bility. So we can say that r. K s P is equal to us times us or US squared, which means taking the square root of the K S P is equal to us. So you&#x27;ll just take the square root of the K S P, which is equal to 2.6 times 10 to the negative nine and you will get an S that is equal to five 0.1 times 10. So the negative five most per liter or Moeller?

Kaden Hamblin · Answer

So here&#x27;s the chemical equation here that we have so silver carbonate as a solid and it goes to ah, two moles of silver in a quick solution plus carbonate. So the K S P value our expression is shown by a G plus squared N C 03 to minus. Okay, So the concentration of silver equals two times 0.32 Solar because there&#x27;s two, most of it came equals 0.64 muller and be scroll down here. So then the concentration of see a three to minus is equal to straight up 0.32 0.3 to Mueller. So now we can throw that back into the Caspian value expression. All right, keep saying that. And so we can put 064 squared because, remember, it&#x27;s squared. It&#x27;s still squared. Even though we multiply that by two, it is different. Uh, we times 0.32 that if you plug it into your calculator, equals 1.31 times 10 cleaner, naked and forth Now is the answer

Sara Ross · Answer

value ability of lead carbonate 298 Kelvin, given a K s P of 7.40 times 10 to the negative 14 the first thing we&#x27;re going to want to do is actually right out the equilibrium equation for this compound. So given any solid of lead carbonate, we know that it&#x27;s going to break up into its respective ions. And based on what we remember from Polly Atomic ions, you know that lead has a two plus and the carbonate is a two minus in solution. So given this equilibrium expression, we can say that our ke sp, which is 7.40 times 10 to the negative 14 But just to save a little time, I&#x27;ll just write K S P is equal to the concentrations of the products normally over the concentration of the reactant CE. However, in this case, the only reacted is a solid. So we leave it out of the equation. And if you&#x27;ll notice based on the Moler ratios for everyone, mole of lead, there is one mole of carbonate. So we can actually say that K s P is equal to say s a variable. It stands for Sally ability times itself or us squared. So to solve for S which is written in moles per liter, we&#x27;re going to say that the square root of the K S P is equal to the S. And so, if you go ahead and solve for the square root of 7.40 times, 10 to the negative 14 you&#x27;ll get 2.72 times 10 to the negative. Seven moles per leader equals us. However, this question is actually asking for us to solve for the soluble it Ian grams per liter. So to do that, we&#x27;re going to use the molar masses of lead carbonate, which in this case is equal to 267 grams per mole, and we&#x27;re gonna multiply that by the most cheerleader. So you multiply 2.72 times 10 to the negative seven moles, her leader times 267 grams per mole. You will get the final answer, which is 7.2 times ton. So the negative five grams per liter equals s

Charotte Mcadam · Answer

the song Ability product constant, which is our chaos. P value is Theo equilibrium constant for a solid substance that is dissolved in an a clear solution. So this and indicates the level at which off salute is able to dissolve in solution. So just as an example here, the most soluble substances the hierarchy SP Valley, will be. So the chaos p off magnesium carbonate, which is NGC of three, is 2.6 times 10 to the minus nine. On In this podcast, we can just simply calculate the soul ability off MG CEOs three in water. So given that we already have the K S P value of MG CEOs, three week congenitally on net Ionic equation off M G C 03 is an equilibrium with an an ionic on a katana counterpart. So it&#x27;s calculate the soul ability and water. We set the concentration of m G two plus two us. So when K s P is equal to M G two plus concentration will supply by CEO three to minus concentration. This is equal to ask multiplied by s so essentially that&#x27;s s squared. So r k sp value equals s squared. So what we need to do is square root are s value that we&#x27;ve set equal to x squared in order to find DK s P. So we generate value 5.1 times 10 to the minus five.

Problem

A saturated solution of nickel(II) sulfide contai…

Problem 60 Medium Difficulty

$K_{\mathrm{sp}}$ for magnesium carbonate, $\mathrm{MgCO}_{3},$ has a value $3.5 \times 10^{-8}$ at $25^{\circ} \mathrm{C}$ . Calculate the solubility of magnesium carbonate in mol $/ \mathrm{L}$ and $\mathrm{g} / \mathrm{L}$ at $25^{\circ} \mathrm{C}$ .

Answer

$1.73 \times 10^{-5} \frac{g}{L}$

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$1.73 \times 10^{-5} \frac{g}{L}$

Introductory Chemistry

Nadia L.

Allea C.

Karli S.

Jacquelin H.

Liquids - Intro

Comparison Of Gases Liquids And Solids

Steven S. Zumdahl, Donald J. DeCosteIntroductory Chemistry

Nadia L.

Allea C.

Karli S.

Jacquelin H.

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Introductory Chemistry