Question
(Kaganov) Prove that $\left(a_1+a_2+\ldots+a_m\right)^2 \leq m\left(a_1^2+\ldots+\right.$ $a_m{ }^2$ ) for any real numbers $a_i$
Step 1
Step 1: We start with the expression we want to prove: \((a_1 + a_2 + \ldots + a_m)^2 \leq m(a_1^2 + a_2^2 + \ldots + a_m^2)\). Show more…
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