00:01
Let us write the shear stress distribution in a fully developed pi flow.
00:04
So for fully developed pie flow, the shear stress can be written as tau -w is equal to minus r divided by 2, multiplied by del p divided by del x, where del p represent the pressure drop and del x is the length along the tube.
00:20
So at radius at any radius r1, we can write, we can write, considering the first case, consider, consider.
00:31
Consider first case.
00:33
Consider first case.
00:37
Here we can write, here we can write, here we can write, tau w1, tau w1 is equals to minus r divided by 2, del p, del p, del p, del p, del p, divided by del x.
00:51
So we will substitute the value of r 0 .015 divided by 2 multiplied by the value of del p divided by delta x is given as, minus 4 .5 multiplied by 10 to the power of 3.
01:07
So from here we get tau w1 is equal to 33 .75, 33 .75 pascal.
01:18
So this is tau 1.
01:20
This is the shear force in the first case.
01:23
So this is sheer force in first case.
01:27
Now we will calculate the shear force in second case...