00:01
So we first have some constants.
00:05
The temperature up temperature, i wish the knife is heated, is 1345 degrees fahrenheit.
00:17
And so we can say that then t sub h be equaling to 5 ninths multiply by 1345 degrees fahrenheit minus 32.
00:34
And this is giving us then 730 degrees celsius.
00:40
The temperature at which the knife is cooled is 500 degrees fahrenheit, converting to celsius.
00:48
5 ninth multiplied by 500 minus 32 is going to be 260 degrees celsius.
00:58
We can say that the heat lost by the carbon steel knife, the heat lost by the carbon steel knife, would be equaling the sum at sum of i m c sub s c of i delta t so essentially the mass of the carbon steel knife multiplied by the sum of the product between the specific key capacity and the change in temperature taken at each of those temperature ranges that are listed in the table so with that we can say that the total heat lost by the knife would be equal to the total heat gained by the water and the copper.
01:55
And so we can say then that sigma i, msum c .s.
02:01
C .i delta t.
02:03
This would be equaling than the mass of the water, specific heat capacity of the water, times the change in temperature of the water, plus the mass of the copper times the specific heat capacity of the copper times the change in temperature of the copper...