Question
Knowing that link $D E$ is $\frac{1}{8}$ in. thick and 1 in. wide, determine the normal stress in the central portion of that link when$(a) \theta=0,(b) \theta=90^{\circ}$.
Step 1
Since it is a rectangle, the area can be calculated as: Area = width × thickness = 1 in × (1/8) in = 1/8 in² Now, let's analyze the forces acting on the link DE for each case: (a) When θ = 0°, the force acting on the link DE is purely axial, meaning it is Show more…
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