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Problem 63 Easy Difficulty

Knowing that the coefficients of friction between the component $I$ and member $B C$ of the mechanism of Prob. 12.62 are $\mathrm{m}_{\mathrm{s}}=0.35$ and $\mathrm{m}_{k}=0.25,$ determine $(a)$ the maximum allowable constant speed $v_{B}$ if the component is not to slide on $B C$ while being transferred, $(b)$ the values of $u$ for which sliding is impending.

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Video Transcript

Hello, friends. Here it is. Given a parallel link mechanism A B C. D is used to transport our component i between manufacturing process at stations E f and G picking it up component I yes, picking up at angle zero degree Onda depositing. So the next station next station at one. Critically it is given that we see all which remains her gentle and link a V and C D rotate at constant rate in our tickle plane. Yeah, if yeah coefficient of friction between the component I on member busy hot um us is 0.35 That is a static friction. Andi Kinetic friction is 1 to 5. Then first part calculate maximum speed off week if component not slide on B c And in second part we have to find the theater. For Pidge, sliding is impending. Let us the starts alway First we will draw the free body diagram off the component I wait off the component acts vertically downward Normal reaction on the friction and having normal force. I am in tow air in this direction and here normal acceleration is we square by route. This is angle Tito. It varies not taking submission off force along X direction. This is considered to be positive. So you may write f It's called Toe. I am a and cause of theater. We can write the mass in terms off. Wait. The weight divided by G Normal acceleration is we square by rope in two cause of theater. See equation one actually me, please. Commission off forces along by direction and minus bait. Toby minus bait Y g by road. Sign off the top. So from ever being question actually, please Normal reaction having developed one minus square off speed at me. Upon ruin to the sign up, Peter. Maximum friction. Maybe us into it so it would be us. Developed one minus square off his speed. Upon ruin to the sign up. Data for component not to slight have must be less than half mix so we can subdue the value here from equation one and two wait. Divided by G square off speed upon root cause off theater Toby Less than us developed one minus We square white G into row. Sign up today. So from ever be question square off velocity Bilby less than Mewes g into rue upon cause off Fotopoulos New us sign opted out se equation tree fuck satisfy Fight the condition off an equality condition off in equality we squared. B max must be less than are equal toe minimum value off um us G into row divided by cause of theater. Pless um, us silent theater, which occurred when cause off the top plus mu s scientific heavy maximum. That's de upon the off theater. Toby, cause of the topless US sign off the top Must be zero. So from here, you may get minus. I know Peter Plus Mu s car sitter Tau zero. So turn off theater, Toby New s on Dhere. Us is given 135 So theater will be 10 in worse off 0.35 So this angle you will get 19.29 degrees. Oh, okay. Come answer apart. A a maximum Bellu off velocity is the square. Max would be U S G into rope upon because of the topless, um, us sign off theater here. Um, us. It's called to 10 off theater so we can write. We square Max Toby G into rope 10 off theater upon cause it er plus 10 theater into science theater. Now substituting the value G is 32.2. Roux is given 10 by 12 ft and 10 off 19.29 upon cause off. 19.29 plus 10 off 19.29 And to sign off. 19.29 on solving it. Maximum speed you will get. Yeah, 2.98 fit per second. No, I answer for a second part B and Tita may very from 90 degree to one. A two degree equation. Third becomes square off. Velocity used the occasion. Third should be less than us G into row upon because off l populus us. Sign off. Alpa here and fight is 1 80 degree by necesito So we have major 19 point tonight. So, Alfa having the value 1 60 point 71 degree substitute develop We have a pending motion. All right, So the left foot Peter Toby 19.29 Degree on go the right. Yeah, for theater, Toby 1 60.7 degree. That's all for it. Thanks for watching it

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Watch More Solved Questions in Chapter 12

Video Transcript

Ferdinand Beer, Jr., E. Russell Johnston, David Mazurek

Vector Mechanics for Engineers: Statics and Dynamics

Elyse Gonzalez

Christina Krawiec

Andy Chen

Zachary Mitchell

This textbook answer is only visible when subscribed! Please subscribe to view the answer

Vector Mechanics for Engineers: Statics and Dynamics

Elyse Gonzalez

Christina Krawiec

Andy Chen

Zachary Mitchell

Ferdinand Beer, Jr., E. Russell Johnston, David Mazurek Vector Mechanics for Engineers: Statics and Dynamics

Elyse Gonzalez

Christina Krawiec

Andy Chen

Zachary Mitchell

Ferdinand Beer, Jr., E. Russell Johnston, David Mazurek

Vector Mechanics for Engineers: Statics and Dynamics