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Knowing that the coefficients of friction between the component $I$ and member $B C$ of the mechanism of Prob. 12.62 are $\mathrm{m}_{\mathrm{s}}=0.35$ and $\mathrm{m}_{k}=0.25,$ determine $(a)$ the maximum allowable constant speed $v_{B}$ if the component is not to slide on $B C$ while being transferred, $(b)$ the values of $u$ for which sliding is impending.

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Physics 101 Mechanics

Chapter 12

Kinetics of Particles: Newton’s Second Law

Newton's Laws of Motion

Cornell University

Rutgers, The State University of New Jersey

University of Michigan - Ann Arbor

Hope College

Lectures

03:28

Newton's Laws of Motion are three physical laws that, laid the foundation for classical mechanics. They describe the relationship between a body and the forces acting upon it, and its motion in response to those forces. These three laws have been expressed in several ways, over nearly three centuries, and can be summarised as follows: In his 1687 "Philosophiæ Naturalis Principia Mathematica" ("Mathematical Principles of Natural Philosophy"), Isaac Newton set out three laws of motion. The first law defines the force F, the second law defines the mass m, and the third law defines the acceleration a. The first law states that if the net force acting upon a body is zero, its velocity will not change; the second law states that the acceleration of a body is proportional to the net force acting upon it, and the third law states that for every action there is an equal and opposite reaction.

09:37

Isaac Newton (4 January 1643 – 31 March 1727) was an English mathematician, physicist, astronomer, theologian, and author (described in his own day as a "natural philosopher") who is widely recognised as one of the most influential scientists of all time and a key figure in the scientific revolution. His book Philosophiæ Naturalis Principia Mathematica ("Mathematical Principles of Natural Philosophy"), first published in 1687, laid the foundations of classical mechanics. Newton also made seminal contributions to optics, and he shares credit with Gottfried Wilhelm Leibniz for developing the infinitesimal calculus.

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Knowing that the coefficie…

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(II) In Fig. 35 the coeffi…

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(II) $(a)$ Suppose the coe…

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(II) In Fig. 4-56 the coef…

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04:42

A block sliding down a $20…

Hello, friends. Here it is. Given a parallel link mechanism A B C. D is used to transport our component i between manufacturing process at stations E f and G picking it up component I yes, picking up at angle zero degree Onda depositing. So the next station next station at one. Critically it is given that we see all which remains her gentle and link a V and C D rotate at constant rate in our tickle plane. Yeah, if yeah coefficient of friction between the component I on member busy hot um us is 0.35 That is a static friction. Andi Kinetic friction is 1 to 5. Then first part calculate maximum speed off week if component not slide on B c And in second part we have to find the theater. For Pidge, sliding is impending. Let us the starts alway First we will draw the free body diagram off the component I wait off the component acts vertically downward Normal reaction on the friction and having normal force. I am in tow air in this direction and here normal acceleration is we square by route. This is angle Tito. It varies not taking submission off force along X direction. This is considered to be positive. So you may write f It's called Toe. I am a and cause of theater. We can write the mass in terms off. Wait. The weight divided by G Normal acceleration is we square by rope in two cause of theater. See equation one actually me, please. Commission off forces along by direction and minus bait. Toby minus bait Y g by road. Sign off the top. So from ever being question actually, please Normal reaction having developed one minus square off speed at me. Upon ruin to the sign up, Peter. Maximum friction. Maybe us into it so it would be us. Developed one minus square off his speed. Upon ruin to the sign up. Data for component not to slight have must be less than half mix so we can subdue the value here from equation one and two wait. Divided by G square off speed upon root cause off theater Toby Less than us developed one minus We square white G into row. Sign up today. So from ever be question square off velocity Bilby less than Mewes g into rue upon cause off Fotopoulos New us sign opted out se equation tree fuck satisfy Fight the condition off an equality condition off in equality we squared. B max must be less than are equal toe minimum value off um us G into row divided by cause of theater. Pless um, us silent theater, which occurred when cause off the top plus mu s scientific heavy maximum. That's de upon the off theater. Toby, cause of the topless US sign off the top Must be zero. So from here, you may get minus. I know Peter Plus Mu s car sitter Tau zero. So turn off theater, Toby New s on Dhere. Us is given 135 So theater will be 10 in worse off 0.35 So this angle you will get 19.29 degrees. Oh, okay. Come answer apart. A a maximum Bellu off velocity is the square. Max would be U S G into rope upon because of the topless, um, us sign off theater here. Um, us. It's called to 10 off theater so we can write. We square Max Toby G into rope 10 off theater upon cause it er plus 10 theater into science theater. Now substituting the value G is 32.2. Roux is given 10 by 12 ft and 10 off 19.29 upon cause off. 19.29 plus 10 off 19.29 And to sign off. 19.29 on solving it. Maximum speed you will get. Yeah, 2.98 fit per second. No, I answer for a second part B and Tita may very from 90 degree to one. A two degree equation. Third becomes square off. Velocity used the occasion. Third should be less than us G into row upon because off l populus us. Sign off. Alpa here and fight is 1 80 degree by necesito So we have major 19 point tonight. So, Alfa having the value 1 60 point 71 degree substitute develop We have a pending motion. All right, So the left foot Peter Toby 19.29 Degree on go the right. Yeah, for theater, Toby 1 60.7 degree. That's all for it. Thanks for watching it

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