00:01
Hello everyone here it is given that radius of each pulley is 200 millimeter that is 0 .2 meter.
00:14
Friction is 0.
00:15
We have to calculate internal forces at j on the frame.
00:41
First drawing fbd of the frame and pulley.
00:59
Here it will be vx, vy.
01:15
This is 360.
01:29
This is 360.
01:39
Now taking moment of course about a point to be 0, you will get 1 .8 into bx minus 2 .6 into 360 will minus 0 .2 into 360 must be 0.
02:11
So bx you will get 560 newton.
02:25
Now fvd off, this is b point.
02:53
Here it is by.
02:56
This is bx, which is 560 newton.
03:12
That is ex.
03:17
This is ey, 1 .5 meter, 2 .4 meter.
04:07
Now submission of moment of force about e, that must be 0...