L-Gulose can be prepared from D-glucose by a route that begins with oxidation to D-glucaric acid, which cyclizes to form two six-memberedring lactones. Separating the lactones and treating them with sodium amalgam, $\mathrm{Na}(\mathrm{Hg}),$ reduces the $-\mathrm{CO}_{2} \mathrm{H}$ group to a primary alcohol and the lactone to an aldehyde, giving D-glucose and L-gulose. What are the structures of the two lactones, and which one is reduced to L-gulose?