00:01
I'll be going over question number 48.
00:05
And it gives you the case you value, gives you an equation of no plus oxygen gas, giving you an 02 gas.
00:15
And it gives you different equations, and you have to find out the value of equilibrium constant.
00:22
So for part 8, it says no gas plus 1 half 02 gas, yields n -o -2 gas.
00:36
So if you look at so k -k -1 is going to be equal to n -o -2 gas squared divided by oxygen gas and then nos nos but with two moles that's raised the second power.
01:15
K -e -2 is going to be the the same but everything's half.
01:24
So 2 and around by 2 is 1.
01:29
2 and around by 2 is 1.
01:30
And then 1 to run by 2 is 1 1 half.
01:37
So when you look at the relationship, k .e .1, let me erase this.
01:47
K .e .1 is equal to k .e .2 to the 1 half.
01:55
Since you're given that k .e .1 is 5 times 10 to the 14...